“contrails are contrails and chemtrails are chemtrails and never the twain do meet. they don't meet on a graph. this clearly and obviously has the math showing that chemtrails are a very different thing than contrails.
Make a graph of the length of the trails that planes leave. How many planes don’t leave any trail? how many plane trails are 5, 6, 7, 8, 9, 10 etc, plane lengths long? How many plane trails are 15, 20, 25, 30, etc plane lengths long? How many plane trails are 50, 100, 150, 200 etc plane lengths long? If they all really are just water vapor from the plane then your graph would show a bell curve with one mode, or place with the most occurrences.
What do we actually get? From 1 to 10 plane lengths long the plane trails do make a bell curve with one mode. But there are no plane trails 20, 30, 40, 50 etc plane lengths long. But there are many plane trails over 100 plane lengths long. The graph distinctly shows two very different groups. There is the short contrail group, and the very long chemtrail group. They are definitely two different populations very different from each other. The graph clearly shows that. What makes the chemtrail group so very different from the contrail group? The math shows they obviously are different.
Math proves chemtrails are not water vapor.
Contrails expand and turn into clear air because they are the water vapor from the fuel. Before they expand to 1 wing span they are clear air, and not a cloud. If a visible cloud from the jet is greater than the wing span of the jet it really can’t be just water vapor from the exhaust. If a visible cloud from the jet has expanded to 1 wing spans wide you know what is making it still be visible is not just water vapor.
References are at the end. 1Kg of Jet fuel A1 = approx 1.742 litres
For the beoing 747-300; Range 12 400 kilometers, Wing span 59.6 meters, Fuel capacity 199 158 liters.
The jet fuel chemical formula c12h23 was used, this results in a molecular weight of 167.3.
so 199 158 liters of jet fuel would weigh; ( 199 158 liters / 1.742 liters per kilo = 114 327 kilos of fuel
114 327 kilos = 114 327 000 grams; divided by the molecular weight of 167.3 = 683 365 moles of fuel molecules. The c12 h23 would produce 12 co2 and 11.5 h2o when the fuel is burned. There would be 11.5 water molecules for every fuel molecule. So there would be 683 365 x 11.5 = 7 858 594 moles of water produced when the fuel capacity is burned.
When the exhaust spreads out to the wing span its cross section would be, pi r squared, with r being half the wingspan; or 59.6 meters / 2 = 29.8 meters. 29.8 meters x 29.8 meters = 888 square meters times pi 3.14 = 2 788 square meters. 1 kilometer is 1 000 meters so the plane’s 12 400 kilometer range is 12 400 000 meters. Over the 12 400 000 meter range there would be 2 788 square meters times 12 400 000 meters long = 34 571 200 000 cubic meters. A cubic meter is 1 000 liters. So a cloud 1 wing span wide over the plane’s range would be 34 571 200 000 cubic meters x 1 000 liters per cubic meter = 34 571 200 000 000 liters.
So, as the plane flies it releases 7 858 594 moles of water into 34 571 200 000 000 liters, in its 1 wingspan wake.
By the time the exhaust spreads out to the wing span of the plane, the plane has deposited 7 858 594 moles of water divided by 34 571 200 000 000 liters = 0.00 000 22731 moles of water per liter into the air. That is 2.2731 millionths of a mole of water per liter. As the exhaust spreads out more than one wing span that water gets diluted exponentially as the cross section increases by the square of the radius.
If you can still see the exhaust from the ground after it has spread out to the wing span of the plane, you can be certain it isn’t the water from the exhaust making the air visible.
Jet fuel formula from https://web.anl.gov/PCS/acsfuel/preprint%20archive/Files/33_4_LOS%20ANGELES_09-88_0875.pdf
The chemical formula c12h23 was used to represent jet A in the computer program.
This results in a molecular weight of 167.3.
114 327 kilos = 114 327 000 grams divided by the molecular weight 167.3 = 683 365 moles of fuel molecules . the c12h23 produce 12 co2 + 11.5 h2o, or 2 c12h23 produce 24 co2 + 23 h2o.
683 365 moles of c12h23 produce 683 365 x 23 = 15 717 395 / 2 = 7 858 697.5 moles of water.
So burning the entire fuel capacity of the 747-300 would produce 7 858 697.5 moles of water.
From http://www.airliners.net/aviation-forums/tech_ops/read.main/200513/
1Kg of Jet A1 = approx 1.742 litres
From beoing http://www.boeing.com/boeing/commercial/747family/pf/pf_classics.page
For the 747-300 Range 12 400 kilometers, Wing span 59.6 meters, Fuel capacity 199 158 liters.
Jet fuel formula from https://web.anl.gov/PCS/acsfuel/preprint%20archive/Files/33_4_LOS%20ANGELES_09-88_0875.pdf
The chemical formula c12h23 was used to represent jet A in the computer program. This results in a molecular weight of 167.3.
i saw an investigative reporter, G Edward Griffin, saying that planes leaving chemtrails happen in NATO countries, but not in non-NATO countries, thus they likely have a political motive. do planes act differently depending on the politics of the people they are flying over?
https://www.youtube.com/watch?v=rsWpSPBwA-w “ david chanley